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Solve the System Using the Inverse Method {x+2y+3z=10x+y+z=2x2z=1\left\{ \begin{array} { l } x + 2 y + 3 z = 10 \\x + y + z = 2 \\x - 2 z = - 1\end{array} \right.

Question 224

Multiple Choice

Solve the system using the inverse method.
- {x+2y+3z=10x+y+z=2x2z=1\left\{ \begin{array} { l } x + 2 y + 3 z = 10 \\x + y + z = 2 \\x - 2 z = - 1\end{array} \right.


A) x = -11, y = 18, z = -5
B) x = 27, y = 38, z = 13
C) x = 10, y = 0, z = 0
D) x = -13, y = 28, z = -5

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