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Solve the Problem x+y=3,000y4xx0y0\begin{array}{l}x+y=3,000 \\y \geq 4 x \\x \geq 0 \\y \geq 0\end{array}

Question 209

Multiple Choice

Solve the problem.
-A person with no more than $3,000 to invest plans to place the money in two investments, telecommunications and pharmaceuticals. The telecommunications investment is to be no more than 4 times the pharmaceuticals
Investment. Write a system of inequalities to describe the situation. Let x = amount to be invested in
Telecommunications and y = amount to be invested in pharmaceuticals. A)
x+y=3,000y4xx0y0\begin{array}{l}x+y=3,000 \\y \geq 4 x \\x \geq 0 \\y \geq 0\end{array}

B)
x+y3,0004xyx0y0\begin{array}{l}x+y \leq 3,000 \\4 x \leq y \\x \geq 0 \\y \geq 0\end{array}

C)
x+y3,000x4yx0y0\begin{array}{l}x+y \leq 3,000 \\x \leq 4 y \\x \geq 0 \\y \geq 0\end{array}

D)
x+y=3,000x4yx0y0\begin{array}{l}x+y=3,000 \\x \leq 4 y \\x \geq 0 \\y \geq 0\end{array}

Correct Answer:

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