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Find an Equation for the Line with the Given Properties y=13x+133y = \frac { 1 } { 3 } x + \frac { 13 } { 3 }

Question 97

Multiple Choice

Find an equation for the line with the given properties.
-Perpendicular to the line y = -3x + 4; containing the point (-4, 3) A) y=13x+133y = \frac { 1 } { 3 } x + \frac { 13 } { 3 }
B) y=3x+133y = 3 x + \frac { 13 } { 3 }
C) y=13x+133y = - \frac { 1 } { 3 } x + \frac { 13 } { 3 }
D) y=3x+133y = - 3 x + \frac { 13 } { 3 }

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