Solve the Problem $( x + 3 ) ^ { 2 } + ( y - 2 ) ^ { 2 } = 16$

Multiple Choice

Solve the problem.
-Find the equation of a circle in standard form with center at the point (-3, 2) and tangent to the line y = 4. A) $( x + 3 ) ^ { 2 } + ( y - 2 ) ^ { 2 } = 16$
B) $( x - 3 ) ^ { 2 } + ( y + 2 ) ^ { 2 } = 16$
C) $( x - 3 ) ^ { 2 } + ( y + 2 ) ^ { 2 } = 4$
D) $( x + 3 ) ^ { 2 } + ( y - 2 ) ^ { 2 } = 4$