Solve the Problem $( x - 3 ) ^ { 2 } + ( y + 5 ) ^ { 2 } = 36$

Multiple Choice

Solve the problem.
-Find the equation of a circle in standard form that is tangent to the line x = -3 at (-3, 5) and also tangent to the line x = 9. A) $( x - 3 ) ^ { 2 } + ( y + 5 ) ^ { 2 } = 36$
B) $( x + 3 ) ^ { 2 } + ( y + 5 ) ^ { 2 } = 36$
C) $( x + 3 ) ^ { 2 } + ( y - 5 ) ^ { 2 } = 36$
D) $( x - 3 ) ^ { 2 } + ( y - 5 ) ^ { 2 } = 36$