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Solve the System in Terms of the Arbitrary Variable X x3y+z=13x - 3 y + z = 13

Question 395

Multiple Choice

Solve the system in terms of the arbitrary variable x.
- x3y+z=13x - 3 y + z = 13
3xyz=33 x - y - z = 3


A) {(x,x4,3x+1) }\{ ( x , x - 4,3 x + 1 ) \}
B) {(0,4,1) }\{ ( 0 , - 4,1 ) \}
C) {(x,x4,2x) }\{ ( x , x - 4,2 x ) \}
D) {(x,x4,2x+1) }\{ ( x , x - 4,2 x + 1 ) \}

Correct Answer:

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