Find the inverse, if it exists, for the matrix.
-

\left[ \begin{array} { r r r r } 0 & 5 & 0 & - 2 \\ 6 & 15 & - 3 & - 4 \\ 12 & 10 & - 6 & - 2 \\ 18 & 0 & - 6 & 0 \end{array} \right]

A)

\left[ \begin{array} { r r r r } - \frac { 1 } { 3 } & - \frac { 3 } { 5 } & - 1 & - 2 \\ \frac { 1 } { 3 } & \frac { 2 } { 5 } & 1 & \frac { 1 } { 2 } \\ - \frac { 1 } { 3 } & - \frac { 1 } { 5 } & - 1 & - \frac { 1 } { 2 } \\ \frac { 1 } { 6 } & 0 & \frac { 1 } { 3 } & 0 \end{array} \right]

B)

\left[ \begin{array} { c c c c } \frac { 1 } { 3 } & - \frac { 1 } { 3 } & \frac { 1 } { 3 } & - \frac { 1 } { 6 } \\\frac { 3 } { 5 } & - \frac { 2 } { 5 } & \frac { 1 } { 5 } & 0 \\1 & - 1 & 1 & \frac { 1 } { 3 } \\- \frac { 3 } { 2 } & - 1 & \frac { 1 } { 2 } & 0\end{array} \right]

C) The inverse does not exist.
D)

\left[ \begin{array} { c c c c } - \frac { 1 } { 3 } & \frac { 1 } { 3 } & - \frac { 1 } { 3 } & \frac { 1 } { 6 } \\- \frac { 3 } { 5 } & \frac { 2 } { 5 } & - \frac { 1 } { 5 } & 0 \\- 1 & 1 & - 1 & \frac { 1 } { 3 } \\- 2 & 1 & - \frac { 1 } { 2 } & 0\end{array} \right]

Use the Gauss-Jordan Method to Solve the System of Equations −2x−8y=−6−8x−32y=6\begin{array} { l } - 2 x - 8 y = - 6 \\- 8 x - 32 y = 6\end{array}−2x−8y=−6−8x−32y=6​

Multiple Choice