For the Equation, Determine the Constants a and B That $$\frac { x } { ( x + 8 ) ( x - 8 ) } = \frac { A } { ( x + 8 ) } + \frac { B } { ( x - 8 ) }$$

Multiple Choice

For the equation, determine the constants A and B that make the equation an identity.
- $$\frac { x } { ( x + 8 ) ( x - 8 ) } = \frac { A } { ( x + 8 ) } + \frac { B } { ( x - 8 ) }$$

A) $\mathrm { A } = \frac { 1 } { 2 } , \mathrm {~B} = \frac { 1 } { 2 }$
B) $\mathrm { A } = \frac { 1 } { 2 } , \mathrm {~B} = 1$
C) $A = 1 , B = \frac { 1 } { 2 }$
D) $\mathrm { A } = - \frac { 1 } { 2 } , \mathrm {~B} = \frac { 1 } { 2 }$