Solved

A Triangle with Vertices at (X1, Y1), (X2, Y2), and (X3

Question 325

Multiple Choice

A triangle with vertices at (x1, y1) , (x2, y2) , and (x3, y3) has area equal to the absolute value of D, where D=12x1y11x2y21x3y31D = \frac { 1 } { 2 } \left| \begin{array} { l l l } x _ { 1 } & y _ { 1 } & 1 \\x _ { 2 } & y _ { 2 } & 1 \\x _ { 3 } & y _ { 3 } & 1\end{array} \right| Find the area of the triangle having vertices at P, Q, and R.
- P(3,3) ,Q(0,5) ,R(4,2) \mathrm { P } ( - 3 , - 3 ) , \mathrm { Q } ( 0,5 ) , \mathrm { R } ( 4,2 )


A) 38
B) 41
C) 0
D) 412\frac { 41 } { 2 }

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions