Solve the Problem $A = \left[ \begin{array} { l l } 2 & - 1 \\ 3 & - 2 \end{array} \right]$

Multiple Choice

Solve the problem.
-Given $A = \left[ \begin{array} { l l } 2 & - 1 \\ 3 & - 2 \end{array} \right]$ and $B = \left[ \begin{array} { r r } 0 & - 1 \\ 4 & 3 \end{array} \right]$ , find $A B$ and $B A$ .

A)
$\mathrm { AB } = \left[ \begin{array} { l l } 4 & 1 \\ 8 & 3 \end{array} \right] ; \mathrm { BA } = \left[ \begin{array} { r r } 3 & - 2 \\ - 1 & 2 \end{array} \right]$
B)
$\mathrm { AB } = \left[ \begin{array} { r r } - 4 & - 5 \\ - 8 & - 9 \end{array} \right] ; \mathrm { BA } = \left[ \begin{array} { r r } - 3 & 2 \\ 17 & - 10 \end{array} \right]$

C)
$\mathrm { AB } = \left[ \begin{array} { r r } - 3 & 2 \\ 17 & - 10 \end{array} \right] ; \mathrm { BA } = \left[ \begin{array} { r r } - 4 & - 5 \\ - 8 & - 9 \end{array} \right]$
D)

$\mathrm { AB } = \left[ \begin{array} { r r } 0 & 1 \\ 12 & - 6 \end{array} \right] ; \mathrm { BA } = \left[ \begin{array} { r r } 0 & 1 \\ 12 & - 6 \end{array} \right]$