Solve the Problem $13 \mathrm {~m}$ And Ranges from 8 To $18 \mathrm {~m}$

Multiple Choice

Solve the problem.
-Tides go up and down in a 14.8-hour period. The average depth of a certain river is $13 \mathrm {~m}$ and ranges from 8 to $18 \mathrm {~m}$ . The variation can be approximated by a sine curve. Write an equation that gives the approximate variation $y$ , if $x$ is the number of hours after midnight and high tide occurs at 10:00 am.

A) $y = 13 \sin \left( \frac { \pi x } { 7.4 } - \frac { 10 \pi } { 7.4 } \right)$
B) $\mathrm { y } = 13 \sin \left( \frac { \pi \mathrm { x } } { 7.4 } - 10 \pi \right)$
C) $\mathrm { y } = 5 \sin \left( \frac { \pi \mathrm { x } } { 7.4 } - \frac { 10 \pi } { 7.4 } \right)$
D) $y = 5 \sin \left( \frac { \pi x } { 7.4 } - \frac { 6.3 \pi } { 7.4 } \right)$