Solve the Problem $2 \mathrm { ft }$ And Released $s ( t ) = 2 \sin \sqrt { 6 } t$

Multiple Choice

Solve the problem.
-A spring with a spring constant of 6 and a 1-unit mass attached to it is stretched $2 \mathrm { ft }$ and released. What is the equation for the resulting oscillatory motion?

A) $s ( t ) = 2 \sin \sqrt { 6 } t$
B) $s ( t ) = \frac { 1 } { 2 } \sin \sqrt { \frac { 1 } { 12 } } t$
C) $s ( t ) = 2 \sin \sqrt { \frac { 1 } { 6 } } t$
D) $s ( t ) = 6 \sin \sqrt { 2 } t$