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Solve the Problem 16ft/sec16 \mathrm { ft } / \mathrm { sec }

Question 154

Multiple Choice

Solve the problem.
-If an object is thrown upward with an initial velocity of 16ft/sec16 \mathrm { ft } / \mathrm { sec } , its height after t\mathrm { t } sec is given by s(t) =16t16t2s ( t ) = 16 t - 16 t ^ { 2 } . Find the maximum height attained by the object. (The object will attain maximum height exactly at the halfway point in terms of the time tt , where t=0t = 0 is at the beginning of the object's flight, and the final time is when the object hits the ground.)


A) 16ft16 \mathrm { ft }
B) 4ft4 \mathrm { ft }
C) 12ft- 12 \mathrm { ft }
D) 0ft0 \mathrm { ft }

Correct Answer:

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