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Solve the Problem 10in.10 \mathrm { in. } By 14in14 \mathrm { in }

Question 305

Multiple Choice

Solve the problem.
-The length of a rectangle is 4 inches more than its width. If 2 inches are taken from the length and added to the width, the figure becomes a square with an area of 144 square inches. What are the dimensions of the original figure?


A) 10in.10 \mathrm { in. } by 14in14 \mathrm { in } .
B) 10in.10 \mathrm { in. } by 12in12 \mathrm { in } .
C) 12 in. by 12 in.
D) 8in.8 \mathrm { in. } by 12in12 \mathrm { in } .

Correct Answer:

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