Use Descartesʹ Rule of Signs to Determine the Possible Number $$2 x ^ { 8 } + 8 x ^ { 6 } + 7 x ^ { 4 } + 3 x ^ { 2 } + 8 = 0$$

Multiple Choice

Use Descartesʹ Rule of Signs to determine the possible number of positive real zeros and the possible negative real zeros for the function.
- $$2 x ^ { 8 } + 8 x ^ { 6 } + 7 x ^ { 4 } + 3 x ^ { 2 } + 8 = 0$$

A) Positive (4) , negative (4)
B) Positive (4) , negative ( 0 )
C) Positive $( 0 )$ , negative $( 4 )$
D) Positive $( 0 )$ , negative $( 0 )$