Use Descartesʹ Rule of Signs to Determine the Possible Number $$2 x ^ { 5 } - 2 x ^ { 4 } + 6 x ^ { 3 } - 3 = 0$$

Multiple Choice

Use Descartesʹ Rule of Signs to determine the possible number of positive real zeros and the possible negative real zeros for the function.
- $$2 x ^ { 5 } - 2 x ^ { 4 } + 6 x ^ { 3 } - 3 = 0$$

A) Positive (1) , negative $( 3,1 )$
B) Positive $( 4,2,0 )$ , negative ( $0 )$
C) Positive $( 3,1 )$ , negative $( 3,1 )$
D) Positive $( 3,1 )$ , negative $( 0 )$