Use Descartesʹ Rule of Signs to Determine the Possible Number $$- 3 x ^ { 4 } - 2 x ^ { 3 } - 6 x ^ { 2 } - 4 x + 2 = 0$$

Multiple Choice

Use Descartesʹ Rule of Signs to determine the possible number of positive real zeros and the possible negative real zeros for the function.
- $$- 3 x ^ { 4 } - 2 x ^ { 3 } - 6 x ^ { 2 } - 4 x + 2 = 0$$

A) Positive $( 2,0 )$ , negative $( 2,0 )$
B) Positive (1) , negative (1)
C) Positive (1) , negative $( 3,1 )$
D) Positive (1) , negative (2)