Use Descartesʹ Rule of Signs to Determine the Possible Number $$2 x ^ { 6 } - 3 x ^ { 4 } - 8 x ^ { 3 } + 6 x ^ { 2 } - 3 x = 0$$

Multiple Choice

Use Descartesʹ Rule of Signs to determine the possible number of positive real zeros and the possible negative real zeros for the function.
- $$2 x ^ { 6 } - 3 x ^ { 4 } - 8 x ^ { 3 } + 6 x ^ { 2 } - 3 x = 0$$

A) Positive $( 2,0 )$ , negative $( 3,1 )$
B) Positive $( 3,1 )$ , negative $( 2,0 )$
C) Positive $( 3,1 )$ , negative (2)
D) Positive $( 2,0 )$ , negative $( 0 )$