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Find the Center-Radius Form of the Equation of the Circle (3,0)( 3,0 )

Question 65

Multiple Choice

Find the center-radius form of the equation of the circle.
-center (3,0) ( 3,0 ) , radius 19\sqrt { 19 }


A) (x+3) 2+y2=19( x + 3 ) ^ { 2 } + y ^ { 2 } = 19
B) (x3) 2+y2=19( x - 3 ) ^ { 2 } + y ^ { 2 } = 19
C) x2+(y3) 2=361x ^ { 2 } + ( y - 3 ) ^ { 2 } = 361
D) (x3) 2+y2=19( x - 3 ) ^ { 2 } + y ^ { 2 } = \sqrt { 19 }

Correct Answer:

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