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Describe the Transformations and Give the Equation for the Graph f(x)=xf ( x ) = \sqrt { x }

Question 183

Multiple Choice

Describe the transformations and give the equation for the graph.
- Describe the transformations and give the equation for the graph. -  A)  It is the graph of  f ( x )  = \sqrt { x }  translated 5 units to the right, shrunken vertically by a factor of  \frac { 1 } { 3 }  and translated 4 units up. The equation is  y = \frac { 1 } { 3 } \sqrt { x + 5 } + 4   B)  It is the graph of  f ( x )  = \sqrt { x }  translated 5 units to the right, shrunken vertically by a factor of  \frac { 1 } { 3 }  and translated 4 units up. The equation is  \mathrm { y } = \frac { 1 } { 3 } \sqrt { \mathrm { x } - 5 } + 4   C)  It is the graph of  f ( x )  = \sqrt { x }  translated 5 units to the right, stretched vertically by a factor of 3 and translated 4 units up. The equation is  y = 3 \sqrt { x + 5 } + 4  D)  It is the graph of  f ( x )  = \sqrt { x }  translated 5 units to the right, stretched vertically by a factor of 3 and translated 4 units up. The equation is  y = 3 \sqrt { x - 5 } + 4


A) It is the graph of f(x) =xf ( x ) = \sqrt { x } translated 5 units to the right, shrunken vertically by a factor of 13\frac { 1 } { 3 } and translated 4 units up. The equation is y=13x+5+4y = \frac { 1 } { 3 } \sqrt { x + 5 } + 4

B) It is the graph of f(x) =xf ( x ) = \sqrt { x } translated 5 units to the right, shrunken vertically by a factor of 13\frac { 1 } { 3 } and translated 4 units up. The equation is y=13x5+4\mathrm { y } = \frac { 1 } { 3 } \sqrt { \mathrm { x } - 5 } + 4

C) It is the graph of f(x) =xf ( x ) = \sqrt { x } translated 5 units to the right, stretched vertically by a factor of 3 and translated 4 units up. The equation is y=3x+5+4y = 3 \sqrt { x + 5 } + 4
D) It is the graph of f(x) =xf ( x ) = \sqrt { x } translated 5 units to the right, stretched vertically by a factor of 3 and translated 4 units up. The equation is y=3x5+4y = 3 \sqrt { x - 5 } + 4

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