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Find a General Term an for the Geometric Sequence a1=16,r=4a _ { 1 } = - \frac { 1 } { 6 } , r = 4

Question 126

Multiple Choice

Find a general term an for the geometric sequence.
- a1=16,r=4a _ { 1 } = - \frac { 1 } { 6 } , r = 4


A) an=164n1a _ { n } = - \frac { 1 } { 6 } \cdot 4 ^ { n - 1 }
B) an=16+18(n1) a _ { n } = - \frac { 1 } { 6 } + \frac { 1 } { 8 } ( n - 1 )
C) an=16+14(n1) \mathrm { a } _ { \mathrm { n } } = - \frac { 1 } { 6 } + \frac { 1 } { 4 } ( \mathrm { n } - 1 )
D) an=(16) 111+18a _ { n } = \left( - \frac { 1 } { 6 } \right) ^ { 11 - 1 } + \frac { 1 } { 8 }

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