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Solve the Problem 11ft11 \mathrm { ft } Per Second, Then Its Height Is Given By

Question 128

Multiple Choice

Solve the problem.
-If an object is thrown upward with an initial velocity of 11ft11 \mathrm { ft } per second, then its height is given by h=11t2+44th = - 11 t ^ { 2 } + 44 t . What is its maximum height?


A) 44ft44 \mathrm { ft }
B) 33ft33 \mathrm { ft }
C) 66ft66 \mathrm { ft }
D) 22ft22 \mathrm { ft }

Correct Answer:

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