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    College Algebra and Trigonometry
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    Exam 10: Analytic Geometry
  5. Question
    Graph the Hyperbola\[\frac { y ^ { 2 } } { 25 } - \frac { x ^ { 2 } } { 36 } = 1\]
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Graph the Hyperbola y225−x236=1\frac { y ^ { 2 } } { 25 } - \frac { x ^ { 2 } } { 36 } = 125y2​−36x2​=1

Question 158

Question 158

Multiple Choice

Graph the hyperbola.
- y225−x236=1\frac { y ^ { 2 } } { 25 } - \frac { x ^ { 2 } } { 36 } = 125y2​−36x2​=1
 Graph the hyperbola. - \frac { y ^ { 2 } } { 25 } - \frac { x ^ { 2 } } { 36 } = 1    A)    B)     C)    D)


A)
 Graph the hyperbola. - \frac { y ^ { 2 } } { 25 } - \frac { x ^ { 2 } } { 36 } = 1    A)    B)     C)    D)
B)
 Graph the hyperbola. - \frac { y ^ { 2 } } { 25 } - \frac { x ^ { 2 } } { 36 } = 1    A)    B)     C)    D)

C)
 Graph the hyperbola. - \frac { y ^ { 2 } } { 25 } - \frac { x ^ { 2 } } { 36 } = 1    A)    B)     C)    D)
D)
 Graph the hyperbola. - \frac { y ^ { 2 } } { 25 } - \frac { x ^ { 2 } } { 36 } = 1    A)    B)     C)    D)

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