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  2. Topic
    Mathematics
  3. Study Set
    College Algebra and Trigonometry
  4. Exam
    Exam 10: Analytic Geometry
  5. Question
    Graph the Hyperbola\[\frac { x ^ { 2 } } { 4 } - \frac { y ^ { 2 } } { 36 } = 1\]
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Graph the Hyperbola x24−y236=1\frac { x ^ { 2 } } { 4 } - \frac { y ^ { 2 } } { 36 } = 14x2​−36y2​=1

Question 30

Question 30

Multiple Choice

Graph the hyperbola.
- x24−y236=1\frac { x ^ { 2 } } { 4 } - \frac { y ^ { 2 } } { 36 } = 14x2​−36y2​=1
 Graph the hyperbola. - \frac { x ^ { 2 } } { 4 } - \frac { y ^ { 2 } } { 36 } = 1    A)    B)    C)    D)


A)
 Graph the hyperbola. - \frac { x ^ { 2 } } { 4 } - \frac { y ^ { 2 } } { 36 } = 1    A)    B)    C)    D)
B)
 Graph the hyperbola. - \frac { x ^ { 2 } } { 4 } - \frac { y ^ { 2 } } { 36 } = 1    A)    B)    C)    D)
C)
 Graph the hyperbola. - \frac { x ^ { 2 } } { 4 } - \frac { y ^ { 2 } } { 36 } = 1    A)    B)    C)    D)
D)
 Graph the hyperbola. - \frac { x ^ { 2 } } { 4 } - \frac { y ^ { 2 } } { 36 } = 1    A)    B)    C)    D)

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