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Solve the Problem D=L2+W2D = \sqrt { L ^ { 2 } + W ^ { 2 } }

Question 548

Multiple Choice

Solve the problem.
-The length of the diagonal of a rectangle is given by D=L2+W2D = \sqrt { L ^ { 2 } + W ^ { 2 } } where LL and WW are the length and width of the rectangle. What is the length of the diagonal, D, of a rectangle that is 83 inches long and 22 inches wide? Round your answer to the nearest tenth of an inch, if necessary.


A) 80in80 \mathrm { in } .
B) 10.2in10.2 \mathrm { in } .
C) 42.7in42.7 \mathrm { in } .
D) 85.9in85.9 \mathrm { in } .

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