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Solve the Problem =x= \mathrm { x } X= gpa X = \text { gpa }

Question 45

Multiple Choice

Solve the problem.
-Consider the following printout. HYPOTHESIS: VARIANCE X =x= \mathrm { x }
X= gpa X = \text { gpa }
SAMPLE MEAN OF X =2.6919= 2.6919
SAMPLE VARIANCE OF X=.19000X = .19000
SAMPLE SIZE OF X=217X = 217
HYPOTHESIZED VALUE (x) =2.8( \mathrm { x } ) = 2.8
 VARIANCE Xx=.1081z=3.65324\begin{aligned}\text { VARIANCE } X - x & = - .1081 \\z & = - 3.65324\end{aligned}
Suppose we tested Ha:μ<2.8H _ { \mathrm { a } } : \mu < 2.8 . Find the appropriate rejection region if we used α=.05\alpha = .05 .


A) Reject if z<1.645\mathrm { z } < - 1.645 .
B) Reject if z>1.96\mathrm { z } > 1.96 or z<1.96\mathrm { z } < - 1.96 .
C) Reject if z>1.645z > 1.645 or z<1.645z < - 1.645 .
D) Reject if z<1.96z < - 1.96 .

Correct Answer:

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