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The Probability Distribution Shown Below Describes a Population of Measurements x15913p(x)14141414\begin{array}{l|cccc}\hline x & 1 & 5 & 9 & 13 \\\hline p(x) & \frac{1}{4} & \frac{1}{4} & \frac{1}{4} & \frac{1}{4} \\\hline\end{array}

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The probability distribution shown below describes a population of measurements that
can assume values of 1, 5, 9, and 13, each of which occurs with the same frequency: x15913p(x)14141414\begin{array}{l|cccc}\hline x & 1 & 5 & 9 & 13 \\\hline p(x) & \frac{1}{4} & \frac{1}{4} & \frac{1}{4} & \frac{1}{4} \\\hline\end{array}

Consider taking samples of n=2n = 2 measurements and calculating xˉ\bar { x } for each sample. Construct the probability histogram for the sampling distribution of xˉ\bar { x } .

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