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Solve the Problem an=100(0.2)n\mathrm { a } _ { \mathrm { n } } = 100 ( 0.2 ) ^ { \mathrm { n } }

Question 192

Multiple Choice

Solve the problem.
-The amount of decay in kilograms of a radioactive isotope each month is given by the sequence whose general term is an=100(0.2) n\mathrm { a } _ { \mathrm { n } } = 100 ( 0.2 ) ^ { \mathrm { n } } , where n\mathrm { n } is the number of the month. Find the amount of decay in the third month, and find the total amount of decay in the first three months. Round to the nearest tenth, if necessary.


A) 0 kg;0.2 kg0 \mathrm {~kg} ; 0.2 \mathrm {~kg}
B) 60 kg;120 kg60 \mathrm {~kg} ; 120 \mathrm {~kg}
C) 800 kg;1400 kg800 \mathrm {~kg} ; 1400 \mathrm {~kg}
D) 0.8 kg;24.8 kg0.8 \mathrm {~kg} ; 24.8 \mathrm {~kg}

Correct Answer:

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