Solve
-The Hypotenuse of a Right Triangle Is 9 Feet $( \sqrt { 137 } + 9 ) \mathrm { ft }$

Multiple Choice

Solve.
-The hypotenuse of a right triangle is 9 feet long. One leg of the triangle is 5 feet longer then the other leg. Find the perimeter of the triangle.

A) $( \sqrt { 137 } + 9 ) \mathrm { ft }$
B) $\left( \frac { 5 } { 2 } + \frac { \sqrt { 137 } } { 2 } \right) \mathrm { ft }$
C) $( \sqrt { 137 } - 9 ) \mathrm { ft }$
D) $\left( - \frac { 5 } { 2 } + \frac { \sqrt { 137 } } { 2 } \right) \mathrm { ft }$