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-A Ball Is Thrown Upward with an Initial Velocity h=4.9t2+21t+110h = - 4.9 t ^ { 2 } + 21 t + 110

Question 172

Multiple Choice

Solve.
-A ball is thrown upward with an initial velocity of 21 meters per second from a cliff that is 70 meters high. The height of the ball is given by the quadratic equation h=4.9t2+21t+110h = - 4.9 t ^ { 2 } + 21 t + 110 where h\mathrm { h } is in meters and t\mathrm { t } is the time in seconds since the ball was thrown. Find the time that the ball will be 40 meters from the ground. Round your answer to the nearest tenth of a second.


A) 7.3sec7.3 \mathrm { sec }
B) 7.4sec7.4 \mathrm { sec }
C) 6.6sec6.6 \mathrm { sec }
D) 6.5sec6.5 \mathrm { sec }

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