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Solve Using the Addition Principle $x + \frac { 2 } { 11 } \geq \frac { 8 } { 11 }$

Question 58

Multiple Choice

Solve using the addition principle. Graph and write set-builder notation for the answer.
- $x + \frac { 2 } { 11 } \geq \frac { 8 } { 11 }$
$Solve using the addition principle. Graph and write set-builder notation for the answer. - x + \frac { 2 } { 11 } \geq \frac { 8 } { 11 } A) \left\{ x \mid x > \frac { 3 } { 11 } \right\} B) \left\{ x \mid x \geq \frac { 6 } { 11 } \right\} C) \left\{ x \mid x < \frac { 3 } { 11 } \right\} D) \left\{ x \mid x \leq \frac { 6 } { 11 } \right\}$

A) $\left\{ x \mid x > \frac { 3 } { 11 } \right\}$
$Solve using the addition principle. Graph and write set-builder notation for the answer. - x + \frac { 2 } { 11 } \geq \frac { 8 } { 11 } A) \left\{ x \mid x > \frac { 3 } { 11 } \right\} B) \left\{ x \mid x \geq \frac { 6 } { 11 } \right\} C) \left\{ x \mid x < \frac { 3 } { 11 } \right\} D) \left\{ x \mid x \leq \frac { 6 } { 11 } \right\}$
B) $\left\{ x \mid x \geq \frac { 6 } { 11 } \right\}$
$Solve using the addition principle. Graph and write set-builder notation for the answer. - x + \frac { 2 } { 11 } \geq \frac { 8 } { 11 } A) \left\{ x \mid x > \frac { 3 } { 11 } \right\} B) \left\{ x \mid x \geq \frac { 6 } { 11 } \right\} C) \left\{ x \mid x < \frac { 3 } { 11 } \right\} D) \left\{ x \mid x \leq \frac { 6 } { 11 } \right\}$
C) $\left\{ x \mid x < \frac { 3 } { 11 } \right\}$
$Solve using the addition principle. Graph and write set-builder notation for the answer. - x + \frac { 2 } { 11 } \geq \frac { 8 } { 11 } A) \left\{ x \mid x > \frac { 3 } { 11 } \right\} B) \left\{ x \mid x \geq \frac { 6 } { 11 } \right\} C) \left\{ x \mid x < \frac { 3 } { 11 } \right\} D) \left\{ x \mid x \leq \frac { 6 } { 11 } \right\}$
D) $\left\{ x \mid x \leq \frac { 6 } { 11 } \right\}$
$Solve using the addition principle. Graph and write set-builder notation for the answer. - x + \frac { 2 } { 11 } \geq \frac { 8 } { 11 } A) \left\{ x \mid x > \frac { 3 } { 11 } \right\} B) \left\{ x \mid x \geq \frac { 6 } { 11 } \right\} C) \left\{ x \mid x < \frac { 3 } { 11 } \right\} D) \left\{ x \mid x \leq \frac { 6 } { 11 } \right\}$

Solve Using the Addition Principle x+211≥811x + \frac { 2 } { 11 } \geq \frac { 8 } { 11 }x+112​≥118​

Multiple Choice

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Solve Using the Addition Principle $x + \frac { 2 } { 11 } \geq \frac { 8 } { 11 }$

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