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Solve the Problem $2.9$ Hours If the Formula $\mathrm { P } ( \mathrm { t } ) = \left( \frac { 1 } { 2 } \right) ^ { t / 2.9 }$

Question 21

Multiple Choice

Solve the problem.
-The half-life of Antimony 111 is $2.9$ hours. If the formula $\mathrm { P } ( \mathrm { t } ) = \left( \frac { 1 } { 2 } \right) ^ { t / 2.9 }$ gives the percent (as a decimal) remaining after time $t$ (in hours) , sketch P versus $t$ .
$Solve the problem. -The half-life of Antimony 111 is 2.9 hours. If the formula \mathrm { P } ( \mathrm { t } ) = \left( \frac { 1 } { 2 } \right) ^ { t / 2.9 } gives the percent (as a decimal) remaining after time t (in hours) , sketch P versus t . A) B) C) D)$

A)
$Solve the problem. -The half-life of Antimony 111 is 2.9 hours. If the formula \mathrm { P } ( \mathrm { t } ) = \left( \frac { 1 } { 2 } \right) ^ { t / 2.9 } gives the percent (as a decimal) remaining after time t (in hours) , sketch P versus t . A) B) C) D)$
B)
$Solve the problem. -The half-life of Antimony 111 is 2.9 hours. If the formula \mathrm { P } ( \mathrm { t } ) = \left( \frac { 1 } { 2 } \right) ^ { t / 2.9 } gives the percent (as a decimal) remaining after time t (in hours) , sketch P versus t . A) B) C) D)$
C)
$Solve the problem. -The half-life of Antimony 111 is 2.9 hours. If the formula \mathrm { P } ( \mathrm { t } ) = \left( \frac { 1 } { 2 } \right) ^ { t / 2.9 } gives the percent (as a decimal) remaining after time t (in hours) , sketch P versus t . A) B) C) D)$
D)
$Solve the problem. -The half-life of Antimony 111 is 2.9 hours. If the formula \mathrm { P } ( \mathrm { t } ) = \left( \frac { 1 } { 2 } \right) ^ { t / 2.9 } gives the percent (as a decimal) remaining after time t (in hours) , sketch P versus t . A) B) C) D)$

Solve the Problem 2.92.92.9 Hours If the Formula P(t)=(12)t/2.9\mathrm { P } ( \mathrm { t } ) = \left( \frac { 1 } { 2 } \right) ^ { t / 2.9 }P(t)=(21​)t/2.9

Multiple Choice

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Solve the Problem $2.9$ Hours If the Formula $\mathrm { P } ( \mathrm { t } ) = \left( \frac { 1 } { 2 } \right) ^ { t / 2.9 }$

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