In 2000, the Population of Sheboygan, WI Was About 113,000 $P ( t ) = 113,000 + 1.85 ^ { t }$

Multiple Choice

In 2000, the population of Sheboygan, WI was about 113,000 and was growing at a rate of 0.85% per year. Find an exponential function that describes the population P in terms of t, the number of Years after 2000.

A) $P ( t ) = 113,000 + 1.85 ^ { t }$
B) $P ( t ) = 113,000 ( 1.0085 ) ^ { t }$
C) $P ( t ) = 113,000 ( 1.85 ) ^ { t }$
D) $P ( t ) = 0.85 ( 113,000 )$