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Factor the Expression That Defines the Function k(w)=w3+7w2+4w+28k ( w ) = w ^ { 3 } + 7 w ^ { 2 } + 4 w + 28

Question 78

Multiple Choice

Factor the expression that defines the function. k(w) =w3+7w2+4w+28k ( w ) = w ^ { 3 } + 7 w ^ { 2 } + 4 w + 28


A) k(w) =(w+7) (w2+4) k ( w ) = ( w + 7 ) \left( w ^ { 2 } + 4 \right)
B) k(w) =w2(w+7) +2(2w+14) k ( w ) = w ^ { 2 } ( w + 7 ) + 2 ( 2 w + 14 )
C) k(w) =(w+7) (w+2) (w2) k ( w ) = ( w + 7 ) ( w + 2 ) ( w - 2 )
D) k(w) =w3+7w2+4w+28k ( w ) = w ^ { 3 } + 7 w ^ { 2 } + 4 w + 28 (Expression is prime)

Correct Answer:

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