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Solve the Absolute Value Equation 3y+42=14y+1\left| \frac { 3 y + 4 } { 2 } \right| = \left| \frac { 1 } { 4 } y + 1 \right|

Question 83

Multiple Choice

Solve the absolute value equation. 3y+42=14y+1\left| \frac { 3 y + 4 } { 2 } \right| = \left| \frac { 1 } { 4 } y + 1 \right|


A) {512,117}\left\{ - \frac { 5 } { 12 } , \frac { 11 } { 7 } \right\}
B) {45,127}\left\{ - \frac { 4 } { 5 } , - \frac { 12 } { 7 } \right\}
C) {23,78}\left\{ \frac { 2 } { 3 } , - \frac { 7 } { 8 } \right\}
D) {14,72}\left\{ \frac { 1 } { 4 } , - \frac { 7 } { 2 } \right\}

Correct Answer:

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