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The Following Output from MINITAB Presents the Results of a Hypothesis

Question 56

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The following output from MINITAB presents the results of a hypothesis test.
Test of mu=53\mathrm { mu } = 53 vs. not =53= 53
The assumed standard deviation 10.310.3
Test of mu=53 m u=53 vs. not =53 =53
The assumed standard deviation 10.3 10.3
N Mean  SE Mean 95% CI PP4449.001.277084(4.88394387,9.890112) 2.5760190.009995\begin{array}{lccccc}\mathrm{N} & \text { Mean } & \text { SE Mean } & 95 \% \text { CI } & \mathrm{P} & \mathrm{P} \\44 & 49.00 & 1.277084 & (4.88394387,9.890112) & -2.576019 & 0.009995 \\\hline\end{array}


What are the null and alternate hypotheses?


A) H0:μ=49.00,H1:μ49.00H _ { 0 } : \mu = 49.00 , H _ { 1 } : \mu \neq 49.00
B) H0:μ=53,H1:μ=49.00H _ { 0 } : \mu = 53 , H _ { 1 } : \mu = 49.00
C) H0:μ=53,H1:μ53H _ { 0 } : \mu = 53 , H _ { 1 } : \mu \neq 53
D) H0:μ53,H1:μ=53H _ { 0 } : \mu \neq 53 , H _ { 1 } : \mu = 53

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