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The Following MINITAB Output Presents A 95%95 \% Confidence Interval Find the Sample Size Needed So That The

Question 107

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The following MINITAB output presents a 95%95 \% confidence interval.

 The assumed sigma =10.5215 Variable N Mean  SE Mean 95%CIx4131.5801.6432(28.359,34.801) \begin{array}{ccccc}\hline {\text { The assumed sigma }=10.5215} & \\\text { Variable } & \mathrm{N} & \text { Mean } & \text { SE Mean } & 95 \% \mathrm{CI} \\\mathbf{x} & 41 & 31.580 & 1.6432 & (28.359,34.801) \\\hline\end{array}
Find the sample size needed so that the 95%95 \% confidence interval will have a margin of err 1.21.2 . rror of


A) 511
B) 18
C) 416
D) 296

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