Urn 1 Contains 3 Red Balls and 4 Black Balls $\frac { 13 } { 24 }$

Multiple Choice

Urn 1 contains 3 red balls and 4 black balls. Urn 2 contains 4 red balls and 2 black balls. Urn 3 contains 6 red balls and 5 black balls. If an urn is selected at random and a ball is
Drawn, find the probability it will be red.

A) $\frac { 13 } { 24 }$
B) $\frac { 1 } { 3 }$
C) $\frac { 379 } { 693 }$
D) $\frac { 13 } { 1386 }$