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The Model  distance ^=3.30+0.235( speed )\sqrt { \hat { \text { distance } } } = 3.30 + 0.235 ( \text { speed } )

Question 578

Multiple Choice

The model  distance ^=3.30+0.235( speed ) \sqrt { \hat { \text { distance } } } = 3.30 + 0.235 ( \text { speed } ) ) can be used to predict the stopping distance (in feet) for a
Car traveling at a specific speed (in mph) . According to this model, about how much distance will a
Car going 65 mph need to stop?


A) 27.0 feet
B) 18.6 feet
C) 729.0 feet
D) 4.3 feet
E) 345.0 feet

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