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In Another Solar System, a Planet Has a Moon That 4.0×105 m4.0 \times 10 ^ { 5 } \mathrm {~m}

Question 41

Multiple Choice

In another solar system, a planet has a moon that is 4.0×105 m4.0 \times 10 ^ { 5 } \mathrm {~m} in diameter. Measurements reveal that this moon takes 3.0×1053.0 \times 10 ^ { 5 } s to make each orbit of diameter 1.8×108 m1.8 \times 10 ^ { 8 } \mathrm {~m} What is the mass of the planet? (G=6.67×1011 Nm2/kg2) \left( G = 6.67 \times 10 ^ { - 11 } \mathrm {~N} \cdot \mathrm { m } ^ { 2 } / \mathrm { kg } ^ { 2 } \right)


A) 2.4×1024 kg2.4 \times 10 ^ { 24 } \mathrm {~kg}
B) 3.4×1024 kg3.4 \times 10 ^ { 24 } \mathrm {~kg}
C) 4.8×1024 kg4.8 \times 10 ^ { 24 } \mathrm {~kg}
D) 1.2×1024 kg1.2 \times 10 ^ { 24 } \mathrm {~kg}
E) 1.7×1024 kg1.7 \times 10 ^ { 24 } \mathrm {~kg}

Correct Answer:

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