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A Beryllium-8 Nucleus at Rest Undergoes Double Alpha Decay as Follows

Question 135

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A beryllium-8 nucleus at rest undergoes double alpha decay as follows:
48Be24He+24He{ } _ { 4 } ^ { 8 } \mathrm { Be } \rightarrow { } _ { 2 } ^ { 4 } \mathrm { He } + { } _ { 2 } ^ { 4 } \mathrm { He }
The known atomic masses are:
24He:4.002603u{ } _ { 2 } ^ { 4 } \mathrm { He } : \quad 4.002603 \mathrm { u }
48Be:8.005305u{ } _ { 4 } ^ { 8 } \mathrm { Be } : \quad 8.005305 \mathrm { u }
What is the kinetic energy of each departing alpha particle? (1u=931.5MeV/c2) \left( 1 \mathrm { u } = 931.5 \mathrm { MeV } / \mathrm { c } ^ { 2 } \right)


A) 130keV130 \mathrm { keV }
B) 92keV92 \mathrm { keV }
C) 180keV180 \mathrm { keV }
D) 46keV46 \mathrm { keV }
E) 65keV65 \mathrm { keV }

Correct Answer:

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