Solved

A Measurement of an Electron's Speed Is 2.0×106 m/s2.0 \times 10 ^ { 6 } \mathrm {~m} / \mathrm { s }

Question 69

Multiple Choice

A measurement of an electron's speed is 2.0×106 m/s2.0 \times 10 ^ { 6 } \mathrm {~m} / \mathrm { s } and has an uncertainty of 10%10 \% . What is the minimum uncertainty in the position of the electron? (melectron =9.11×1031 kg,h=6.626×\left( m _ { \text {electron } } = 9.11 \times 10 ^ { - 31 } \mathrm {~kg} , h = 6.626 \times \right. 1034 Js) \left. 10 ^ { - 34 } \mathrm {~J} \cdot \mathrm { s } \right)


A) 4.9 nm4.9 \mathrm {~nm}
B) 0.58 nm0.58 \mathrm {~nm}
C) 1.5 nm1.5 \mathrm {~nm}
D) 0.87 nm0.87 \mathrm {~nm}
E) 0.29 nm0.29 \mathrm {~nm}

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions