The Excited State of a Certain Atom Is $10 ^ { - 19 } \mathrm {~J}$

Short Answer

The excited state of a certain atom is $3.2 \mathrm { eV } \pm 0.21 \mathrm { eV } . \left( h = 6.626 \times 10 ^ { - 34 } \mathrm {~J} \cdot \mathrm { s } , 1 \mathrm { eV } = 1.60 \times \right.$ $10 ^ { - 19 } \mathrm {~J}$ )
(a) What is the average lifetime of this state, in femtoseconds?
(b) If the excited energy were doubled (to $6.4 \mathrm { eV } \pm 0.21 \mathrm { eV }$ ), how would the lifetime be affected?