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What Is the Surface Temperature of a Star, If Its 1.06×10151.06 \times 10^{15}

Question 173

Multiple Choice

What is the surface temperature of a star, if its radiation peak occurs at a frequency of 1.06×10151.06 \times 10^{15} Hz\mathrm { Hz } ? (c=3.00×108 m/s\left( c = 3.00 \times 10 ^ { 8 } \mathrm {~m} / \mathrm { s } \right. , and the constant in Wien's law is 0.00290 mK) \left. 0.00290 \mathrm {~m} \cdot \mathrm { K } \right)


A) 17,000 K17,000 \mathrm {~K}
B) 14,500 K14,500 \mathrm {~K}
C) 10,200 K10,200 \mathrm {~K}
D) 20,400 K20,400 \mathrm {~K}
E) 19,000 K19,000 \mathrm {~K}

Correct Answer:

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