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What Is the Cutoff (Threshold) Frequency for a Metal Surface 5.42eV5.42 \mathrm { eV }

Question 187

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What is the cutoff (threshold) frequency for a metal surface that has a work function of 5.42eV5.42 \mathrm { eV } ? (1 eV=1.60×1019 J,h=6.626×1034 Js) \left. \mathrm { eV } = 1.60 \times 10 ^ { - 19 } \mathrm {~J} , h = 6.626 \times 10 ^ { - 34 } \mathrm {~J} \cdot \mathrm { s } \right)


A) 1.31×1015 Hz1.31 \times 10 ^ { 15 } \mathrm {~Hz}
B) 5.02×1015 Hz5.02 \times 10^{15} \mathrm {~Hz}
C) 3.01×1015 Hz3.01 \times 10^{15} \mathrm {~Hz}
D) 6.04×1015 Hz6.04 \times 10^{15} \mathrm {~Hz}
E) 2.01×1015 Hz2.01 \times 10^{15} \mathrm {~Hz}

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