A 140-KeV Photon Strikes an Electron and Scatters Through an Angle

Short Answer

A 140-keV photon strikes an electron and scatters through an angle of $120 ^ { \circ }$ from its original direction. (melectron $= 9.11 \times 10 ^{- 31} \mathrm {~kg} , c = 3.00 \times 10 ⁸ \mathrm {~m} / \mathrm { s } , h = 6.626 \times 10 ^{- 34} \mathrm {~J} \cdot \mathrm { s }$ )
(a) What is the wavelength of the photon before scattering?
(b) What is the photon wavelength after scattering?