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A Proton Moving with a Velocity Of 4.0×104 m/s4.0 \times 10 ^ { 4 } \mathrm {~m} / \mathrm { s }

Question 130

Multiple Choice

A proton moving with a velocity of 4.0×104 m/s4.0 \times 10 ^ { 4 } \mathrm {~m} / \mathrm { s } along the +y+ y -axis enters a magnetic field of 0.20 T0.20 \mathrm {~T} directed towards the x- x -axis. What is the magnitude of the magnetic force acting on the proton? (e( e =1.60×1019C= 1.60 \times 10 ^ { - 19 } \mathrm { C } )


A) 8.0×1015 N8.0 \times 10 ^ { - 15 } \mathrm {~N}
B) 1.3×1015 N1.3 \times 10 ^ { - 15 } \mathrm {~N}
C) 2.6×1015 N2.6 \times 10 ^ { - 15 } \mathrm {~N}
D) 3.9×1015 N3.9 \times 10 ^ { - 15 } \mathrm {~N}
E) 0 N0 \mathrm {~N}

Correct Answer:

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