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An Electron Moves with a Speed Of 8.0×106 m/s8.0 \times 10 ^ { 6 } \mathrm {~m} / \mathrm { s }

Question 17

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An electron moves with a speed of 8.0×106 m/s8.0 \times 10 ^ { 6 } \mathrm {~m} / \mathrm { s } along the +x+ x -axis. It enters a region where there is a magnetic field of 2.5 T2.5 \mathrm {~T} , directed at an angle of 6060 ^ { \circ } to the +x+ x -axis and lying in the xyx y -plane.
Calculate the magnitude of the acceleration of the electron. (e=1.60×1019C,me1=9.11×1031\left( e = 1.60 \times 10 ^ { - 19 } \mathrm { C } , m _ { e 1 } = 9.11 \times 10 ^ { - 31 } \right. kg\mathrm { kg } )


A) 1.3×1018 m/s21.3 \times 10 ^ { 18 } \mathrm {~m} / \mathrm { s } ^ { 2 }
B) 3.0×1018 m/s23.0 \times 10 ^ { 18 } \mathrm {~m} / \mathrm { s } ^ { 2 }
C) 0 m/s20 \mathrm {~m} / \mathrm { s } ^ { 2 }
D) 1.3×1018 m/s21.3 \times 10 ^ { - 18 } \mathrm {~m} / \mathrm { s } ^ { 2 }
E) 3.0×1018 m/s23.0 \times 10 ^ { - 18 } \mathrm {~m} / \mathrm { s } ^ { 2 }

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