Solved

A Proton, Starting from Rest, Accelerates Through a Potential Difference 1.0kV1.0 \mathrm { kV }

Question 27

Multiple Choice

A proton, starting from rest, accelerates through a potential difference of 1.0kV1.0 \mathrm { kV } and then moves into a magnetic field of 0.040 T0.040 \mathrm {~T} at a right angle to the field. What is the radius of the proton's resulting orbit? (e=1.60×1019C,mproton =1.67×1027 kg) \left( e = 1.60 \times 10 ^ { - 19 } \mathrm { C } , m _ { \text {proton } } = 1.67 \times 10 ^ { - 27 } \mathrm {~kg} \right)


A) 0.080 m0.080 \mathrm {~m}
B) 0.14 m0.14 \mathrm {~m}
C) 0.11 m0.11 \mathrm {~m}
D) 0.17 m0.17 \mathrm {~m}

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions