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The Current Through A 50−Ω50 - \Omega Resistor Is I=(0.80 A)sin⁡(240t)I = ( 0.80 \mathrm {~A} ) \sin ( 240 t )

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The current through a 50−Ω50 - \Omega resistor is I=(0.80 A)sin⁡(240t)I = ( 0.80 \mathrm {~A} ) \sin ( 240 t ) . What are (a) the current amplitude and (b) the rms current?

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(a) 0.80 A...

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